x^2+0.04x-0.16=0

Solution for x^2+0.04x-0.16=0 equation:

x^2+0.04x-0.16=0

a = 1; b = 0.04; c = -0.16;
Δ = b2-4ac
Δ = 0.042-4·1·(-0.16)
Δ = 0.6416
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.04)-\sqrt{0.6416}}{2*1}=\frac{-0.04-\sqrt{0.6416}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.04)+\sqrt{0.6416}}{2*1}=\frac{-0.04+\sqrt{0.6416}}{2}
$